NOTE: If you were to look at the JavaScript and JavaScript Console, you would see this
// Array.prototype.filter()
// 1. Filter the list of inventors for those who were born in the 1500's
const fifteen = inventors.filter(inventor => (inventor.year >= 1500 && inventor.year< 1600));
console.table(fifteen);
// Array.prototype.map()
// 2. Give us an array of the inventors' first and last names
const fullName = inventors.map(inventor => `${inventor.first} ${inventor.last}`);
console.log(fullName);
// Array.prototype.sort()
// 3. Sort the inventors by birthdate, oldest to youngest
const sorted = inventors.sort((a,b) => a.year > b.year ? 1 : -1);
console.table(sorted);
// Array.prototype.reduce()
// 4. How many years did all the inventors live?
const totalYears = inventors.reduce((total,inventor) => total + (inventor.passed - inventor.year),0);
console.log("Total Years Lived: " + totalYears);
// 5. Sort the inventors by years lived
const oldest = inventors.sort(function(a,b){
const prevGuy = a.passed - a.year;
const nextGuy = b.passed - b.year;
return (prevGuy > nextGuy) ? -1 : 1;
});
console.table(oldest);
// 6. create a list of Boulevards in Paris that contain 'de' anywhere in the name
// https://en.wikipedia.org/wiki/Category:Boulevards_in_Paris
[[ NOTE: To see this, open console log on link page and paste the following code.]]
const category = document.querySelector('.mw-category');
const links = Array.from(category.querySelectorAll('a'));
const de = links
.map(link => link.textContent)
.filter(streetName => streetName.includes('de'));
console.log(de);
// 7. sort Exercise
// Sort the people alphabetically by last name
const alpha = people.sort((last,next)=> {
const [aLast, aFirst] = last.split(', ');
const [bLast, bFirst] = next.split(', ');
return aLast > bLast ? 1 : -1;
});
console.log(alpha);
// 8. Reduce Exercise
// Sum up the instances of each of these
const data = ['car', 'car', 'truck', 'truck', 'bike', 'walk', 'car', 'van', 'bike', 'walk', 'car', 'van', 'car', 'truck' ];
const transportation = data.reduce(function(obj, item){
if(!obj[item]) {
obj[item] = 0;
}
obj[item]++;
return obj;
},{});
console.log(transportation);